Some basic facts
They are easy to
understand!!!!! Suppose
the school said all grading had to be on a bell curve; i.e,
A,B,C,D,F.
The mean for this class is
76.3
2. Next find the standard deviation; i.e., the measure of the
variability of a distribution of scores.
To calculate the standard
deviation follow the following steps:
Calculate the mean
78-76.3
Thus if Jeff's score were calculated a z-score of 78-76.3/14.07=.12.
Jeff's score is very close to the mean.
If we look at Suzy's score, on the other hand, the picture is different.
Her z score is 42-76.3= 34.3/14.07= -2.43.
In short, Suzy's score is more than 2 standard deviations below the mean.
It is significantly discrepant from the mean.
Look at Fred's score. He has a z-score of
1.54. His score is significantly
above the mean but you should see that even with such a high test score
grade it is not as high above the mean as Suzy's is below. The sample
of test takers was not randomly drawn and is therefore not representative
of a large population of people. The distribution is skewed because
of the large number of high scores on this test.
Using this method it would be possible to compare
the relative performance of the scores each training session earned on
the certification test. Would this have been a good procedure; i.e.,
to standardize the scores of each class and award passing status based
on the standardized, z score of each participant within a class?
NO! Do you understand why not? If not you should review more
about statistics in an introductory statistic textbook. This issue
will also be better further clarified in the session on the bell
curve.The problem you should ask yourself is what are the
characteristics of the small sample from which the test scores were
taken?
Those who write and develop reliable and valid
intellectual and achievement tests make certain that the sample is representative
of the overall population demographics; i.e. that the test scores fall
along a normal
distribution-- bell
curve.
Here are some numbers to
practice with if you want more information about how this works.
The simplest
type of standard score is called a z-score. This score is
an indication of the deviation of a score from the mean, or average
score, or a group of scores in relation to the standard deviation.
Let's see how this works. Below is a list of raw test scores that
was earned on an exam.
Jeff 78
Bill 67
Mary 92
Paul
91
Martha 62
Donna 94
Fred
98
Robert 51
Rachel 72
Barbara  81
Peter 61
Leroy 85
Daren 88
Suzy
42
Ron 78
Rick 78
 
Terri
80
  John 78
Mike 68
Tory 82
How would I assign the grades for this class?
The
grades need to be transformed.
standard score(z score)= raw score(test
grade)(X)-mean(M)
standard deviation (S.D.)
1. Find the mean of this class. The mean is the total of
all of the raw scores divided by the number of people
who took the test.
Calculate the deviation
score by subtracting the mean from each test grade.
67-76.3
92-76.3
etc.

You will see that the mean on this
exam was 76.3 and the standard deviation was 14.07. In order to determine
where a test grade would fall if a standardized sample were used the data
is now converted to a z score. This score will assume a mean of 100
and a standard deviation of 14. The z score for each person is obtained
by taking that person's score and subtracting the mean and then dividing
by the standard deviation.
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